Case sensitive
The simplest way to check whether there is a substring in a string is by using the in operator.
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if "text" in "Just a simple text.": print(True) else: print(False) |
output
True
It returns True because “text” is contained in the “Just a simple text” string. When you change the case in the text, it will return False. Look at these examples.
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if "Text" in "Just a simple text.": print(True) else: print(False) |
and
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if "text" in "Just a simple Text.": print(True) else: print(False) |
They both return False because there are different case sizes.
Ignore case
If you want to create a case-insensitive script, you can use the lower function. It will cast all characters in a string to lowercase.
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my_string = "Just a simple text." if my_substring.lower() in my_string.lower(): print(True) else: print(False) |
The output this time is True.
Starts with
With the startswith function, you can check whether the string starts with the chosen substring. This code is case-sensitive.
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my_string = "this is a text" if my_string.startswith("this"): print(True) else: print(False) |
This code returns True.
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my_string = " this is a text" if my_string.startswith("this"): print(True) else: print(False) |
This code returns False if there is a single character before the substring – even space.
Ends with
This function is similar to the endswith function. It returns True each time there is a substring at the end of the string.
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my_string = 'This is a text' if my_string.endswith("text"): print(True) else: print(False) |
Count how many times a substring is present in a string
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my_string1 = "is a text in a text" my_string2 = "Just a normal string" print(my_string1.count("text")) print(my_string2.count("text")) |
The script returns the following output.
2 0
Get a substring position
In order to check the position of the string, use the index function.
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my_string = "This is a text" print(my_string.index("is")) |
output
2
The index function shows the first occurrence of the given string. In this example, the first is inside the word This. Counting starts at 0, so the number is 2.